The dimension of 1/2 ε0E2 is MaLbTc, then the value of a−2b+c is:
1
2
3
4
1
The expression 1/2 ε0E2 represents energy density, which is defined as:
Energy density = Energy /Volume
Dimensions used:
• Energy = ML2T−2
• Volume = L3
Step 1: Find the dimensions of energy density.
Energy density = ML2T−2 /L3
Step 2: Compare with given form MaLbTc. =
a =1, b=−1, c=−2
Step 3: Compute required expression. a −2b+c=1−2(−1)+(−2)=1+2−2=1
Energy density problems can be solved quickly by remembering:
Energy density = ML−1T−2
No need to derive each time in exams.