CUET UG Mathematics (319) - 2025 Question Paper with Solutions

# Q1 of 50

Let A = [aij]n x n be a matrix. Then Match List-I with List-II


List-I


(A) AT = A

(B) AT = -A

(C) —A— = 0

(D) —A—  ≠ 0


List-II


(I) A is a singular matrix

(II) A is a non-singular matrix

(III) A is a skew symmetric matrix

(IV) A is a symmetric matrix


Choose the correct answer from the options given below:

Options :
A.

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

B.

(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

C.

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

D.

(A) - (I), (B) - (II), (C) - (IV), (D) - (III)

Show Answer
Answer :

(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

Solution :

Step 1: Understanding the Concept:

This question tests the knowledge of basic definitions related to matrices, specifically symmetric, skew-symmetric, singular, and non-singular matrices.


Step 3: Detailed Explanation:

Let’s analyze each item in List-I and match it with the correct definition in List-II.


• (A) AT = A: This is the definition of a symmetric matrix. A matrix is symmetric if it is equal to its transpose. This matches with (IV).


• (B) AT = -A: This is the definition of a skew-symmetric matrix. A matrix is skewsymmetric if its transpose is equal to its negative. This matches with (III).


• (C) —A— = 0: The determinant of a matrix being zero is the condition for the matrix to be a singular matrix. This matches with (I).


• (D) —A— ≠ 0: The determinant of a matrix being non-zero is the condition for the matrix to be a non-singular matrix. Such matrices have an inverse. This matches with (II).


Step 4: Final Answer:

Combining the matches, we get: (A) → (IV) (B) → (III) (C) → (I) (D) → (II) This combination corresponds to option (2).

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