CUET UG Mathematics (319) - 2025 Question Paper with Solutions

# Q1 of 50

Let A = [aij]n x n be a matrix. Then Match List-I with List-II


List-I


(A) AT = A

(B) AT = -A

(C) —A— = 0

(D) —A—  ≠ 0


List-II


(I) A is a singular matrix

(II) A is a non-singular matrix

(III) A is a skew symmetric matrix

(IV) A is a symmetric matrix


Choose the correct answer from the options given below:

Options
A.

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

B.

(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

C.

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

D.

(A) - (I), (B) - (II), (C) - (IV), (D) - (III)

Show Answer
Correct Answer

(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

Solution

The correct answer is (A) - (IV), (B) - (III), (C) - (I), (D) - (II).

Let us analyze each term in List-I and match it with the correct description in List-II:

1. Matching (A): AT = A
By definition, a square matrix A is called a symmetric matrix if it is equal to its transpose, which is written as:
AT=A
Therefore, (A) matches with (IV).

2. Matching (B): AT = -A
By definition, a square matrix A is called a skew-symmetric matrix if the transpose of the matrix is equal to the negative of the matrix itself, which is written as:
AT=−A
Therefore, (B) matches with (III).

3. Matching (C): |A| = 0
A square matrix A is defined as a singular matrix if its determinant is equal to zero, which is represented by:
|A|=0
Therefore, (C) matches with (I).

4. Matching (D): |A| ≠ 0
A square matrix A is defined as a non-singular matrix if its determinant is not equal to zero, which is represented by:
|A|≠0
Therefore, (D) matches with (II).

Combining all the individual matches, we get:
(A) → (IV), (B) → (III), (C) → (I), and (D) → (II).

Want to study from this teacher?

Questions