Question

In the vicinity of the triple point, the equation of liquid-vapour boundary in the 𝑷 βˆ’ 𝑻 phase diagram for ammonia is π₯𝐧 𝑷 = πŸπŸ’. πŸ‘πŸ– βˆ’ πŸ‘πŸŽπŸ”πŸ‘/𝑻, where P is pressure (in Pa) and 𝑻 is temperature (in K). Similarly, the solid-vapour boundary is given by π₯𝐧 𝑷 = πŸπŸ•. πŸ—πŸ βˆ’ πŸ‘πŸ•πŸ“πŸ’/𝑻. The temperature at the triple point is ___________ K (round off to one decimal place).

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Answer :

Correct answer is : 195.19

L i q u i d v a p o u r , ln ⁑ P = 24.38 βˆ’ 3063 T

S o l i d v a p o u r , ln ⁑ P = 27.92 βˆ’ 3754 T

At triple point temperature of solid, liquid and vapour is same

∴ Equating

24.38 βˆ’ 3063 T = 27.92 βˆ’ 3754 T

Now,

Multiplying by β€˜T’ on both sides

24.38 T – 3063 = 27.92 T – 3754

3.54 T = 691

T = 195.197 K

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